**Passage 9:** **Hardness of water** is expressed in ppm (parts per million) as equivalents. A sampl — Mole Concept and Some Basic Concepts of Chemistry Chemistry Question
Question
**Passage 9:** **Hardness of water** is expressed in ppm (parts per million) as $CaCO_3$ equivalents. A $100 \text{ mL}$ sample of hard water contains $12 \text{ mg}$ of $MgSO_4$ (MW=120) and $11.1 \text{ mg}$ of $CaCl_2$ (MW=111). What are the **moles of $CaCO_3$ equivalent** to the $MgSO_4$ in the sample?
Answer: A
💡 Solution & Explanation
$\text{moles } MgSO_4 = 0.012 / 120 = 10^{-4} \text{ mol}$. <br>Since valency is same, $1 \text{ mol } MgSO_4 \equiv 1 \text{ mol } CaCO_3 = 10^{-4} \text{ mol}$.
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