**Passage 4:** If the percentage of in the above mixture is , how many moles of are produced by ? — Mole Concept and Some Basic Concepts of Chemistry Chemistry Question
Question
**Passage 4:** If the percentage of $Cu$ in the above mixture is $31.75\%$, how many moles of $NO_2$ are produced by $Ag$?
Answer: C
💡 Solution & Explanation
$\text{Mass Cu} = 3.175 \text{ g}$. $\text{Mass Ag} = 10 - 3.175 = 6.825 \text{ g}$. <br>$\text{moles Ag} = 6.825 / 108 \approx 0.063$. <br>Since $1 \text{ Ag} \rightarrow 1 \text{ NO}_2$, moles of $NO_2 = 0.063$.
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