**Passage 1:** The limiting reagent in a chemical reaction is the reactant that is completely consum — Mole Concept and Some Basic Concepts of Chemistry Chemistry Question
Question
**Passage 1:** The limiting reagent in a chemical reaction is the reactant that is completely consumed first, limiting the amount of product formed. For the reaction: $2A + 3B \rightarrow 4C + 5D$, if $5 \text{ moles of A}$ and $9 \text{ moles of B}$ are reacted, which is the limiting reagent?
💡 Solution & Explanation
Ratio required $A:B = 2:3 = 0.66$. <br>Ratio provided $A:B = 5:9 = 0.55$. <br>Since provided $A/B <$ required $A/B$, the denominator ($B$) is in relatively larger supply, or checking moles/stoichiometry: $A$ needs $5 \times (3/2) = 7.5 \text{ mol B}$. We have 9. $B$ needs $9 \times (2/3) = 6 \text{ mol A}$. We have 5. Thus, $A$ is limiting. *Correction:* $5/2 = 2.5$; $9/3 = 3$. Smaller value is $A$. $A$ is the limiting reagent.