of a mixture of and was heated. The volume of evolved was at STP. Calculate the percentage of in the — Mole Concept and Some Basic Concepts of Chemistry Chemistry Question
Question
$5.0 \text{ g}$ of a mixture of $NaHCO_3$ and $Na_2CO_3$ was heated. The volume of $CO_2$ evolved was $560 \text{ mL}$ at STP. Calculate the percentage of $NaHCO_3$ in the mixture.
Answer: $84\%$
💡 Solution & Explanation
$2NaHCO_3 \rightarrow Na_2CO_3 + CO_2 + H_2O$. <br>$\text{moles } CO_2 = 0.56 / 22.4 = 0.025 \text{ mol}$. <br>$\text{moles } NaHCO_3 = 2 \times 0.025 = 0.05 \text{ mol}$. <br>$\text{Mass } NaHCO_3 = 0.05 \times 84 = 4.2 \text{ g}$. <br>$\% = (4.2/5.0) \times 100 = 84\%$.
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