A sample of hard water contains of per liter. What is the hardness of the water in ppm (as equivalen — Mole Concept and Some Basic Concepts of Chemistry Chemistry Question

💡 Solution & Explanation

$\text{moles } CaSO_4 = 204/136 = 1.5 \times 10^{-3} \text{ mol}$. <br>$1 \text{ mol } CaSO_4 \equiv 1 \text{ mol } CaCO_3$. <br>$\text{Mass } CaCO_3 \text{ eq} = 1.5 \times 10^{-3} \times 100 = 0.15 \text{ g} = 150 \text{ mg}$. <br>$\text{Hardness} = 150 \text{ mg/L} = 150 \text{ ppm}$.