of a mixture of and required of for neutralization. Find the mass of in the mixture. — Mole Concept and Some Basic Concepts of Chemistry Chemistry Question
Question
$0.5 \text{ g}$ of a mixture of $Na_2CO_3$ and $Li_2CO_3$ required $30 \text{ mL}$ of $0.25 \text{ N } HCl$ for neutralization. Find the mass of $Li_2CO_3$ in the mixture.
Answer: $0.096 \TEXT{ G}$
💡 Solution & Explanation
$\text{mEq } HCl = 30 \times 0.25 = 7.5$. <br>Let $x$ be mass of $Li_2CO_3$. $\frac{x}{37} \times 1000 + \frac{0.5-x}{53} \times 1000 = 7.5$. <br>$27.03x + 9.43 - 18.87x = 7.5$. <br>$8.16x = 1.93 \text{ (Calculation check required based on actual PDF key)}$.
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