Find the mole fraction of methanol () in a solution containing of methanol and of water. | Mole Concept and Some Basic Concepts of Chemistry — Chem-Mantra

Question

Find the mole fraction of methanol ($CH_3OH$) in a solution containing $32\text{ g}$ of methanol and $36\text{ g}$ of water.

Answer: $0.33$

💡 Solution & Explanation

$\text{moles methanol} = 32 / 32 = 1 \text{ mol}$. <br>$\text{moles water} = 36 / 18 = 2 \text{ mol}$. <br>$\chi = 1 / (1 + 2) = 1/3 \approx 0.33$.

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