How many grams of are required to react with of to form ? — Mole Concept and Some Basic Concepts of Chemistry Chemistry Question
Question
How many grams of $CaO$ are required to react with $852 \text{ g}$ of $P_4O_{10}$ to form $Ca_3(PO_4)_2$?
Answer: $1008 \TEXT{ G}$
💡 Solution & Explanation
$6CaO + P_4O_{10} \rightarrow 2Ca_3(PO_4)_2$. <br>$\text{moles } P_4O_{10} = 852 / 284 = 3 \text{ mol}$. <br>$\text{moles } CaO = 3 \times 6 = 18 \text{ mol}$. <br>$\text{Mass } CaO = 18 \times 56 = 1008 \text{ g}$.
💬Ask on WhatsApp →
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes