**Assertion (A):** Normality of $0.1 \text{ M } H_2SO_4$ is $0.2 \text{ N}$. **Reason (R):** $H_2SO_4$ is a dibasic acid.

Correct answer: A. For an acid, . Since can donate two protons (), .

**Assertion (A):** Normality of is . <br>**Reason (R):** is a dibasic acid. | Mole Concept and Some Basic Concepts of Chemistry — Chem-Mantra

Question

**Assertion (A):** Normality of $0.1 \text{ M } H_2SO_4$ is $0.2 \text{ N}$. <br>**Reason (R):** $H_2SO_4$ is a dibasic acid.

Answer: A

💡 Solution & Explanation

For an acid, $\text{Normality} = \text{Molarity} \times \text{Basicity}$. Since $H_2SO_4$ can donate two protons ($n=2$), $0.1 \text{ M} \times 2 = 0.2 \text{ N}$.

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💡 Solution & Explanation

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