**Assertion (A):** Equivalent weight of in acidic medium is . <br>**Reason (R):** In acidic medium, — Mole Concept and Some Basic Concepts of Chemistry Chemistry Question
Question
**Assertion (A):** Equivalent weight of $KMnO_4$ in acidic medium is $M/5$. <br>**Reason (R):** In acidic medium, $Mn^{7+}$ is reduced to $Mn^{2+}$.
Answer: A
💡 Solution & Explanation
$\text{Equivalent Weight} = \text{Molar Mass} / \text{n-factor}$. In acidic medium, the oxidation state change is from $+7$ to $+2$, which is a transfer of $5$ electrons. Hence $n = 5$. [1, 10]
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