See image — Hydrocarbons Chemistry Question

💡 Solution & Explanation

Correct option: \(\text{C}\). In the presence of peroxides, addition of \(\ce{HBr}\) to an unsymmetrical alkene follows the radical anti-Markovnikov pathway. Recovered question text: 15. Reaction of HBr with propene in the presence of peroxide gives (1) 3–bromo propane (2) Allyl bromide (3) n–propyl bromide (4) Isopropyl bromide