See image — Hydrocarbons Chemistry Question

💡 Solution & Explanation

Correct option: \(\text{C}\). In the presence of peroxides, addition of \(\ce{HBr}\) to an unsymmetrical alkene follows the radical anti-Markovnikov pathway. Recovered question text: 87. The intermediate formed during the addition of HCl to propene in the presence of peroxide is –     (A) (B) (C) (D) CH CHCH Cl CH CH CH CH CHCH CH CH CH 3 2 3 2 2 3 3 3 2 2