See image — Haloalkanes and Haloarenes Chemistry Question

💡 Solution & Explanation

Correct answer: \(\text{C}\). Elimination removes \(\ce{HX}\) from adjacent carbons. Product preference follows substrate structure, anti-periplanar geometry, and Zaitsev/Hofmann control where applicable. Recovered question text: 20. An alkyl halide C6H13Cl reacts with (CH3)3CO K to form two isomeric alkenes (Y) and (Z) (C6H12). Both the alkenes give 2, 3-di methyl butane on hydrogenation. The halide is CH3 CH3 (a) CH3CHCHCH2Cl (b) CH3CH2CH2CHCH2CH3 Cl CH3 CH3 CH3 (c) CH3C CHCH3 (d) CH3C CH2CH2CH3 Cl Cl