See image β Isomerism and Stereochemistry Chemistry Question
Question
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π‘ Solution & Explanation
# Analysis of Isomers and Reaction Pathways **Key observations from the graph:** 1. **A and B are isomers of same energy** β they have identical starting potential energy but differ in structure (spatial arrangement) 2. **Different activation energies** β A+R has a higher activation barrier (solid curve) than B+R (dashed curve), meaning they follow different reaction mechanisms through different transition states 3. **Different products** β A β C and B β D, with C higher in energy than D --- ## Evaluating each statement: **(A) False** β The transition states have *different* activation energies (different heights on PE diagram), so they are not enantiomers. Enantiomers have identical activation energies. **(B) True** β The two transition states are **diastereomers** because: - Both are formed from the same reactants (A+R and B+R) - They have different geometries/structures (different activation barriers) - They are NOT mirror images (which would be enantiomers) - Diastereomers are stereoisomers that are not mirror images β **(C) True** β **A and B are enantiomers** because: - Same molecular formula and connectivity - Same energy (superimposable in 3D space but are non-superimposable mirror images) - This explains why they react with R differently β **(D) True** β **C and D are diastereomers** because: - Both derived from same reactant R but different isomeric starting materials (A vs B) - Different energy levels (C > D on diagram) - Not mirror images of each other β **Answer: B, C, D are all correct.**