See image — Isomerism and Stereochemistry Chemistry Question

💡 Solution & Explanation

# Analysis of Isomerism in Each Compound **Requirements:** A compound must have both: - **Geometrical isomerism** (cis-trans due to C=C double bond with different substituents) - **Enantiomerism** (chiral center with 4 different groups) --- ## Option A: $CH_3CHOHC_2H_5$ - Has one chiral center ($CH$ bearing $OH$) → enantiomerism ✓ - No C=C double bond → **no geometrical isomerism** ✗ --- ## Option B: $CH_3CHOHCOOH$ - Has one chiral center ($CH$ bearing $OH$ and $COOH$) → enantiomerism ✓ - No C=C double bond → **no geometrical isomerism** ✗ --- ## Option C: $CH_3CH=CHCH(CH_3)C_2H_5$ (structure redrawn) The molecule is: $$\text{(CH}_3\text{)CH-CH=CH-CH(CH_3)(C_2H_5)}$$ **Geometrical isomerism:** The C=C double bond has different groups on each carbon: - One carbon: $CH_3$ and $H$ (different) - Other carbon: $CH(CH_3)(C_2H_5)$ and $H$ (different) → Exhibits **cis-trans isomerism** ✓ **Enantiomerism:** The right carbon of the double bond has a chiral center with 4 different groups: $H$, $CH_3$, $C_2H_5$, and the vinyl group → Exhibits **enantiomerism** ✓ --- **Answer: (C)** — It's the only compound with both a C=C (geometrical isomerism) AND a chiral center (enantiomerism).