See image — Isomerism and Stereochemistry Chemistry Question

💡 Solution & Explanation

# Analysis of the Compound Pair **Identifying the structures:** **Left compound:** Two $CH_3$ groups opposite each other on a cyclopropane ring with an $OH$ group - Molecular formula: $C_4H_8O$ **Right compound:** One $CH_3$ group and one $CH_2OH$ group on cyclopropane - Molecular formula: $C_4H_8O$ **Step 1: Check molecular formula** Both compounds have the same molecular formula ($C_4H_8O$), so they are isomers. **Step 2: Determine structural relationship** - Left structure: 1,1-dimethylcyclopropanol (two methyls on same carbon) - Right structure: 1-methyl-2-cyclopropanmethanol (methyl and hydroxymethyl on different positions) The structures have different connectivity and cannot be interconverted by rotation. **Step 3: Assess stereochemistry** Neither structure contains chiral centers or restricted rotation that would create stereoisomers (cis-trans). **Conclusion:** These compounds are **constitutional isomers** (or structural isomers). They have the same molecular formula but different structural arrangements, making them distinct compounds with different chemical and physical properties. **Option C** correctly identifies this relationship.