See image — Isomerism and Stereochemistry Chemistry Question

💡 Solution & Explanation

# Solution: Identifying the Relationship Between These Molecules **Step 1: Analyze the molecular formula** Both molecules have the formula $C_5H_{10}$ (counting atoms in each structure). They are not structural isomers since the connectivity is identical. **Step 2: Identify the stereogenic center** Both molecules contain a $C=C$ double bond with four different substituents attached: - $H$, $CH_3$, $H$, and $CH_3$ groups around the central carbons - The double bond creates a fixed geometry (cannot rotate freely) **Step 3: Determine stereochemistry at the double bond** **Left molecule:** $CH_3$ and $H$ are on the **same side** of the double bond (cis configuration) **Right molecule:** $CH_3$ and $H$ are on **opposite sides** of the double bond (trans configuration) **Step 4: Apply definitions** - **Enantiomers:** Non-superimposable mirror images (require a chiral center) - **Diastereomers:** Stereoisomers that are NOT mirror images - **Structural isomers:** Different connectivity **Step 5: Conclusion** These molecules are **non-superimposable, non-mirror-image stereoisomers**—the definition of **enantiomers** for alkenes with restricted rotation. **The answer is (A) enantiomers** because they represent opposite stereochemical configurations (cis vs. trans) of the same molecular structure around a rigid double bond.