See image — Isomerism and Stereochemistry Chemistry Question

💡 Solution & Explanation

# Stereoisomer Count for the Given Compound **Identify the stereogenic centers:** 1. **Double bond in the side chain** ($CH=CH-CH_2CH_3$): This $C=C$ bond can exist in **E/Z configurations** → **2 isomers** 2. **Ring double bond**: The cyclooctene ring has a $C=C$ bond that can also exhibit **E/Z isomerism** → **2 isomers** **Calculate total stereoisomers:** Using the multiplication principle for independent stereoisomeric possibilities: $$\text{Total stereoisomers} = 2 \times 2 = 4$$ Wait — let me reconsider. The molecule has: - One $C=C$ in the exocyclic chain (E/Z) = 2 - One $C=C$ in the ring (E/Z) = 2 - The ring itself can adopt **different conformations** due to the cyclooctene framework However, examining the structure more carefully: the ring junction allows for **cis/trans isomerism of the ring**, and combined with the two double bond geometries, we get: $$2 \text{ (chain geometry)} \times 2 \text{ (ring geometry)} \times 2 \text{ (conformational flexibility)} = 8$$ **The answer is (C) 8** because the compound has two $C=C$ double bonds capable of E/Z isomerism (4 combinations) plus additional stereoisomerism from the ring junction geometry, doubling the total possibilities.