See image — Isomerism and Stereochemistry Chemistry Question

💡 Solution & Explanation

# Solution: Identifying Asymmetric Carbon Atoms An asymmetric (chiral) carbon atom has **four different groups** attached to it. **Analysis of each option:** **(A) Cyclopropane with Cl and Br:** The carbon bearing both Cl and Br has four different groups attached: - Cl, Br, and two different CH groups (one connected to Br, one to Cl) - **Has asymmetric C** ✓ **(B) N-methylazetidine:** The carbon bearing the N-Me group has: - N-Me group, and three CH₂ groups in different positions of the ring - **Has asymmetric C** ✓ **(C) $C_2H_5IBr$ (Iodoethane bromide/1-bromo-1-iodoethane):** The carbon bearing both I and Br has four different groups: - I, Br, H, and $CH_3$ - **Has asymmetric C** ✓ **(D) $H-\overset{|}{C}-Cl$ structure:** This carbon has: - H, Cl, and two other groups shown (H and Cl again based on the notation) - Actually shows: H, H, Cl, and one more group - **Two hydrogen atoms** make this carbon symmetric - **Does NOT have asymmetric C** ✗ **Answer: (D)** — The carbon atom has two identical hydrogen atoms attached, violating the requirement of four *different* groups for a chiral center.