See image — Isomerism and Stereochemistry Chemistry Question

💡 Solution & Explanation

# Solution: Identifying the Relationship Between Structures I and II **Step 1: Analyze the molecular formula** Both structures I and II contain: - 4 methyl groups (Me) - 2 hydrogen atoms - 1 cyclohexane ring Both have the formula $C_{10}H_{22}$ — they are **isomers**. **Step 2: Compare connectivity (skeletal structure)** - Structure I: 4 methyls attached to the cyclohexane ring at positions 1,2,3,4 - Structure II: 4 methyls attached to the cyclohexane ring at positions 1,2,3,4 The **connectivity is identical** — ruling out constitutional isomers (option C). **Step 3: Examine stereochemistry** - Structure I shows all methyls in **equatorial positions** (more stable conformation) - Structure II shows methyls in **axial and equatorial positions** (less stable conformation) Both structures represent the **same molecule** but in different chair conformations. **Step 4: Determine isomer type** Since these are the same compound viewed in different 3D orientations (different conformations of the cyclohexane ring), they are **conformational isomers**. They can interconvert through rotation around C-C bonds and ring flipping at room temperature. **Answer: (A) Conformational isomers** ✓