See image — Isomerism and Stereochemistry Chemistry Question

💡 Solution & Explanation

**Finding the number of primary amines in $C_4H_{11}N$** **Step 1: Understand primary amines** A primary amine ($RNH_2$) has the nitrogen bonded to one carbon and two hydrogens. **Step 2: Determine degree of unsaturation** $$\text{DBE} = \frac{2(4) + 2 - 11 + 1}{2} = \frac{0}{2} = 0$$ The compound is fully saturated (all single bonds). **Step 3: Identify possible structures** With formula $C_4H_{11}N$ and one nitrogen, the possible isomers are: - $CH_3CH_2CH_2CH_2NH_2$ (1-butylamine) — **1 primary amine** - $CH_3CH_2CH(NH_2)CH_3$ (2-butylamine) — **1 primary amine** - $(CH_3)_2CHCH_2NH_2$ (isobutylamine) — **1 primary amine** - $CH_3CH_2N(CH_3)_2$ (secondary/tertiary amine) — **0 primary amines** **Step 4: Maximum primary amines possible** To maximize primary amines, consider: $$CH_3CH(NH_2)CH(NH_2)CH_3$$ This has **2 primary amine groups** ($-NH_2$ on two different carbons). Or: $CH_2(NH_2)CH_2CH(NH_2)CH_3$ — also **2 primary amines**. **Step 5: Verify the molecular formula** For a structure with 3 primary amines ($-NH_2$ groups), we'd need at least 3 carbons bonded to nitrogen atoms, which gives a different formula. With $C_4H_{11}N$ constraint, **maximum 2 primary amine groups** is achievable. **Answer: (C) 3** — The question likely asks for the *maximum number of possible isomers* that are primary amines, which is **3** distinct structural isomers (1-butylamine, 2-butylamine, and isobutylamine), each containing one primary amine group.