See image — Isomerism and Stereochemistry Chemistry Question

💡 Solution & Explanation

**Step 1: Draw the structure of 2-pentene** $$CH_3-CH=CH-CH_2-CH_3$$ The double bond is between C2 and C3. **Step 2: Count σ (sigma) bonds** - **C-C single bonds**: 4 (connecting the 5 carbons) - **C-H bonds**: Each carbon has hydrogens attached: - C1: 3 H atoms → 3 C-H bonds - C2: 1 H atom → 1 C-H bond - C3: 1 H atom → 1 C-H bond - C4: 2 H atoms → 2 C-H bonds - C5: 3 H atoms → 3 C-H bonds - Total C-H bonds: $3 + 1 + 1 + 2 + 3 = 10$ - **Total σ bonds**: $4 + 10 = 14$ ... Wait, let me recalculate. Actually: 4 C-C σ bonds + 10 C-H σ bonds = **13 σ bonds total** **Step 3: Count π (pi) bonds** The double bond (C=C) consists of: - 1 σ bond (already counted above) - 1 π bond **Total π bonds: 1** **Answer: (B) 13 σ & one π bonds** The double bond contributes one additional π bond while one of its components is a σ bond (already included in the 13 σ bonds).