See image — Isomerism and Stereochemistry Chemistry Question

💡 Solution & Explanation

# Analysis of Isomerism in $C_{100}H_{202}$ **Step 1: Determine the degree of unsaturation** Using the formula: $\text{DBE} = \frac{2C + 2 - H}{2} = \frac{2(100) + 2 - 202}{2} = \frac{0}{2} = 0$ Since DBE = 0, there are **no rings or double bonds** — the compound is fully saturated. **Step 2: Evaluate each isomerism type** - **(A) Metamerism**: Occurs in ethers/amines with different alkyl chains on the heteroatom. Not applicable here (no heteroatom mentioned). - **(D) Tautomerism**: Requires mobile hydrogen atoms between carbonyl/enol groups. Impossible without unsaturation (π bonds). - **(C) Functional isomerism**: Different functional groups (e.g., aldehyde vs. ketone, ether vs. alcohol). Requires structural differences in functional groups, not possible for a saturated hydrocarbon. - **(B) Position and chain isomerism**: - **Chain isomerism**: Different carbon skeleton arrangements (e.g., straight-chain vs. branched alkanes) - **Position isomerism**: Same carbon skeleton with branches at different positions Both are possible for $C_{100}H_{202}$ (a saturated alkane). **Answer: (B) Position and chain isomerism** ✓ Saturated alkanes with 100 carbons can exist as numerous isomers differing only in chain arrangement and branch positions.