See image — Isomerism and Stereochemistry Chemistry Question

💡 Solution & Explanation

# Analysis of Stereoisomeric Structures **Step 1: Identify the stereogenic centers** Structures A, B, C, and D all contain a central carbon bonded to four different groups ($Cl$, $Br$, and two different organic groups), making them chiral molecules. **Step 2: Analyze Structure A** - Central carbon: $Cl$, $Br$, $CH_3$, $C_2H_5$ (all different) - This is a chiral center with a specific 3D arrangement **Step 3: Analyze Structure B** - Central carbon: $Cl$, $Br$, $C_2H_5$, $CH_3$ (same four groups as A) - However, the spatial arrangement is **identical** to A (not a mirror image) - Therefore, A and B are **the same molecule**, not enantiomers **Step 4: Verify other statements** - **B and C are identical**: Structure C also has $Cl$, $Br$, $CH_3$, $C_2H_5$ in the same arrangement ✓ - **A and C are enantiomers**: False — they're identical ✗ - **B and D are enantiomers**: D has a different arrangement and is the mirror image of B ✓ **Conclusion:** Option (B) claims "A and B are enantiomers," but A and B are **identical molecules** with the same 3D spatial arrangement, not mirror images. This statement is **incorrect**. **Answer: (B) is not correct.**