See image — Isomerism and Stereochemistry Chemistry Question

💡 Solution & Explanation

# Solution: Identifying Enantiomers **Enantiomers** are non-superimposable mirror images that require a **chiral center** (stereogenic center) — a carbon bonded to four different groups. ## Analysis of Each Compound: **(1) $CH_3CH_2CH(Cl)CH_3$** - The carbon bearing $Cl$ is bonded to: $CH_3$, $CH_2CH_3$, $Cl$, and $H$ - All four groups are **different** → **Chiral center exists** - This compound **has enantiomers** ✓ **(2) $CH_2CH_2CH_2CH_2Cl$** - No carbon is bonded to four different groups - The terminal carbons have identical $H$ atoms - **No chiral center** ✗ **(3) $CH_3CH_2CH_2CHCl_2$** - The $CHCl_2$ carbon is bonded to: two $Cl$ atoms, $CH_2CH_3$, and $H$ - Has **two identical groups** ($Cl$) → **Not a chiral center** ✗ ## Answer: **(1) only** has an enantiomer because it contains a chiral center with four distinct substituents attached to one carbon atom.