See image — Isomerism and Stereochemistry Chemistry Question

💡 Solution & Explanation

# Analysis of Isomerism in the Given Compound **Step 1: Identify the structural features** The molecule contains: - A $C=C$ double bond (alkene) - Substituents with different spatial arrangements around this double bond - An asymmetric carbon bearing $H$, $COOH$, $CH_3$, and another group **Step 2: Check for geometric isomerism** The $C=C$ double bond has: - Left carbon: two $CH_3$ groups (identical) - Right carbon: $H$ and $COOH$ (different) Since both carbons don't have two *different* groups each, **geometric (cis-trans) isomerism is NOT possible** here. **Step 3: Check for optical isomerism** The right carbon of the double bond is bonded to: - $H$ - $COOH$ - $CH_3$ - The $C=C$ carbon (sp² hybridized) This carbon is **chiral** (four different groups). The molecule can exist as $(E)$ and $(Z)$ enantiomers based on the double bond geometry, but more importantly, it exhibits **optical isomerism** due to this stereogenic center. **Step 4: Verify tautomerism** No keto-enol or other tautomeric equilibrium is readily possible. **Answer: Option (2) — Optical isomerism** The compound exhibits optical isomerism due to the presence of a stereogenic (chiral) center on the right carbon of the double bond system.