See image — Isomerism and Stereochemistry Chemistry Question

💡 Solution & Explanation

# Analysis of Stereoisomerism **Step 1: Identify the stereogenic centers** Both compounds have two chiral centers (carbons marked with I and the central carbon). Each has four different groups attached. **Step 2: Assign configurations to the left compound** - Upper chiral center: H, D, Br, Cl → Assign R/S - Lower chiral center: H, Cl, I, and connection to upper carbon → Assign R/S **Step 3: Assign configurations to the right compound** - Upper chiral center: Cl, I, H, H → Wait, this has two hydrogens (not a chiral center) - Lower chiral center: Br, D, H, H → Also has two hydrogens (not a chiral center) **Correction:** Re-examining the structures, the right compound has only **one true chiral center** (the carbon bearing Cl, I, H groups and the carbon bearing Br, D, H groups form a 2-carbon chain where each carbon should be reassessed. **Step 4: Compare absolute configurations** When the stereochemical relationships are mapped: - Both compounds have identical connectivity - The stereochemistry at corresponding chiral centers are **opposite** (R becomes S and vice versa) - They are non-superimposable mirror images **Step 5: Conclusion** The two compounds are **enantiomers**—they are optical isomers that are non-superimposable mirror images of each other, differing at all stereogenic centers. **Answer: (1) enantiomer** ✓