See image — Isomerism and Stereochemistry Chemistry Question

💡 Solution & Explanation

# Analysis of Optical Activity **Understanding Optical Activity Requirements:** Optical activity requires the presence of **chiral centers** (stereocenters) — carbons bonded to four different groups. --- **Evaluating Option (1):** Structure: $H_2C=CH-C(H)=C(CH_3)(CH(Cl)CH_3)$ - The carbon in $CH(Cl)CH_3$ is bonded to: - $Cl$ - $CH_3$ - $H$ - $C=C$ fragment (different from the above) ✓ **This is a chiral center** → exhibits optical activity --- **Evaluating Option (2):** Structure: $H_3C-CH=C(H_3C)-C(H)=C(CH(CH_3)_2)(H)$ - The carbon in $CH(CH_3)_2$ is bonded to: - Two identical $CH_3$ groups - $H$ - $C=C$ fragment ✗ **This is NOT a chiral center** (has two identical $CH_3$ groups attached) → no optical activity --- **Answer: Option (1)** shows optical activity due to the presence of a chiral center in the $CH(Cl)CH_3$ group.