See image — Isomerism and Stereochemistry Chemistry Question

💡 Solution & Explanation

**Step-by-step solution:** **Step 1: Identify the molecular formulas** - Compound 1: $CH_3-O-CH_2CH_3$ → $C_2H_6O$ (ethyl methyl ether) - Compound 2: $CH_3-CH_2-CH_2OH$ → $C_3H_8O$ (1-propanol) **Step 2: Check if molecular formulas are identical** The compounds have different molecular formulas ($C_2H_6O$ vs $C_3H_8O$), so they cannot be isomers of each other. **Step 3: Identify the type of isomerism** Since both compounds have the same molecular formula is **not** the case here, we need to reconsider. Both structures actually contain: - Compound 1: $CH_3OCH_2CH_3$ = $C_3H_8O$ - Compound 2: $CH_3CH_2CH_2OH$ = $C_3H_8O$ ✓ **Step 4: Classify the isomerism type** Both are $C_3H_8O$ but contain **different functional groups**: - First compound: ether ($-O-$) - Second compound: alcohol ($-OH$) **Step 5: Apply definition** **Functional isomerism** occurs when compounds with the same molecular formula have different functional groups. **Answer: (2) Functional isomerism** — This is the correct answer because the two $C_3H_8O$ compounds differ in their functional groups (ether vs. alcohol), not just the position or chain arrangement.