See image — Isomerism and Stereochemistry Chemistry Question

💡 Solution & Explanation

# E/Z Configuration Analysis To determine E/Z configuration, assign priorities to groups at each double bond carbon using atomic number rules, then check if higher priorities are on the **same side (Z)** or **opposite sides (E)**. ## Option (4) Analysis: **Left carbon ($C_1$):** - $H$ (atomic number 1) - $CH_3$ (atomic number 6) Priority: $CH_3 > H$ → **Priority 1 to $CH_3$, Priority 2 to $H$** **Right carbon ($C_2$):** - $COOH$ (C bonded to: C, O, O | atomic numbers: 6, 8, 8) - $CHO$ (C bonded to: C, H, O | atomic numbers: 6, 1, 8) Comparing: $COOH$ has two oxygens vs $CHO$ has one oxygen. Priority: $COOH > CHO$ → **Priority 1 to $COOH$, Priority 2 to $CHO$** **Configuration Check:** $$H-C_1=C_2-COOH$$ Both Priority 1 groups ($CH_3$ and $COOH$) are on **opposite sides** of the double bond. $$\boxed{\text{E-configuration}}$$ Options (1), (2), and (3) show Z-configuration where Priority 1 groups are on the same side of the double bond.