See image — Isomerism and Stereochemistry Chemistry Question

💡 Solution & Explanation

# Solution **Analyze the first compound:** $HC \equiv C - CH_2 - CH(CH_3) - CH_3$ - Molecular formula: $C_6H_{10}$ - Triple bond between first two carbons (alkyne) **Analyze the second compound:** $CH_3 - C \equiv C - CH(CH_3) - CH_3$ - Molecular formula: $C_6H_{10}$ - Triple bond between carbons 2 and 3 (alkyne) **Check if they are the same compound:** Both have the same molecular formula and functional group (alkyne). However: - **First compound:** Triple bond is terminal (at position 1) - **Second compound:** Triple bond is internal (at position 2-3) The position of the functional group (triple bond) differs between them. **Why not other options?** - **(1) Chain isomer:** ✗ Both have the same carbon skeleton - **(2) Homologous:** ✗ They have identical molecular formulas (not differing by $CH_2$) - **(4) None:** ✗ They are clearly related isomers **Answer: (3) Position isomer** — The triple bond is located at different positions in the carbon chain, making these compounds position isomers of $C_6H_{10}$.