See image — Isomerism and Stereochemistry Chemistry Question

💡 Solution & Explanation

# Finding Correct Match: Compounds with Degree of Unsaturation (D.U.) **Formula for Degree of Unsaturation:** $$\text{D.U.} = \frac{2C + 2 + N - H - X}{2}$$ For hydrocarbons ($C_xH_y$): $$\text{D.U.} = \frac{2C + 2 - H}{2}$$ --- ## Checking each compound: **(i) $C_5H_{10}$:** $$\text{D.U.} = \frac{2(5) + 2 - 10}{2} = \frac{10 + 2 - 10}{2} = \frac{2}{2} = 1$$ ✓ **(ii) $C_4H_6$:** $$\text{D.U.} = \frac{2(4) + 2 - 6}{2} = \frac{8 + 2 - 6}{2} = \frac{4}{2} = 2$$ ✓ **(iii) $C_6H_{14}$:** $$\text{D.U.} = \frac{2(6) + 2 - 14}{2} = \frac{12 + 2 - 14}{2} = \frac{0}{2} = 0$$ ✗ --- ## Conclusion: Compounds (i) and (ii) have **correct D.U. values** (1 and 2 respectively), while (iii) is incorrect (should be 0, not 1). **The answer is (1): (i) & (ii)**