See image — Isomerism and Stereochemistry Chemistry Question

💡 Solution & Explanation

# Solution **Analyzing each structure:** - **Structure A**: Central carbon has $CH_3$, $C_2H_5$, $Cl$, $Br$ (4 different groups) → **Chiral center** - **Structure B**: Central carbon has $C_2H_5$, $CH_3$, $Cl$, $Br$ (4 different groups) → **Chiral center** - **Structure C**: Central carbon has $CH_3$, $C_2H_5$, $Cl$, $Br$ (4 different groups) → **Chiral center** - **Structure D**: Central carbon has $C_2H_5$, $CH_3$, $Cl$, $Br$ (4 different groups) → **Chiral center** **Checking each statement:** **(A) B and C are identical:** Comparing the spatial arrangements—B has the groups in different positions than C. **Not identical** → Statement is **incorrect**. **(B) A and B are enantiomers:** Both have the same four groups ($CH_3$, $C_2H_5$, $Cl$, $Br$) arranged as non-superimposable mirror images. **Correct** ✓ **(C) A and C are enantiomers:** A and C have identical group arrangements (same 3D positions), making them the **same compound**, not enantiomers. **Incorrect** → This is the answer. **(D) B and D are enantiomers:** B and D have the same four groups in mirror-image arrangements. **Correct** ✓ **Answer: (C) is NOT correct** because A and C are identical compounds, not enantiomers.