See image — Isomerism and Stereochemistry Chemistry Question

💡 Solution & Explanation

# Solution **Analyzing the Structure:** The compound has two key stereoisomeric features: ## Geometrical Isomers (x): The double bond $C=C$ has: - Left carbon: $H_3C-$ and $-H$ groups - Right carbon: $-H$ and $-CH_2CH_2CH(OH)CH_3$ groups Since both substituents on each end are different, **cis-trans (E-Z) isomerism** is possible: - **cis isomer** (both large groups on same side) - **trans isomer** (large groups on opposite sides) $$\boxed{x = 2 \text{ geometrical isomers}}$$ ## Optical Isomers (y): The chiral center is the carbon bearing the $OH$ group (marked with $H$ below): $$-CH(OH)CH_3$$ This carbon has 4 different groups attached: - $-OH$ - $-H$ - $-CH_3$ - $-CH_2CH_2-$ (rest of chain) A single chiral center produces **2 enantiomers** (R and S configurations): $$\boxed{y = 2 \text{ optical isomers}}$$ ## Answer: $$x = 2, \quad y = 2$$ **Option (B) is correct** because the compound exhibits 2 geometrical isomers from the $C=C$ double bond and 2 optical isomers from the single chiral center.