See image — Isomerism and Stereochemistry Chemistry Question

💡 Solution & Explanation

# Geometric Isomerism Analysis **Geometric isomerism requires:** A double bond with two different groups on each carbon. **Checking each option:** **(A) Isobutene** $(CH_3)_2C=CH_2$ - One carbon of the $C=C$ has two identical methyl groups - Cannot show geometric isomerism ✗ **(B) Acetone oxime** $CH_3-C(=NOH)-CH_3$ - Structure: $CH_3$ and $CH_3$ on the same carbon - Both groups attached to C are identical - Cannot show geometric isomerism ✗ **(C) Acetophenone oxime** $C_6H_5-C(=NOH)-CH_3$ - Structure: Phenyl group ($C_6H_5$) and methyl group ($CH_3$) attached to the same carbon of $C=N$ - Nitrogen has two different groups: $OH$ and $H$ (implicit) - The $C=N$ double bond can have: - **E-isomer:** phenyl and methyl on same side - **Z-isomer:** phenyl and methyl on opposite sides - Geometric isomerism **is possible** ✓ **(D) Benzophenone oxime** $(C_6H_5)_2C=NOH$ - Both groups attached to C are identical phenyl groups - Cannot show geometric isomerism ✗ **Answer: (C) Acetophenone oxime** — it's the only compound with two *different* groups on the carbon of the $C=N$ double bond, allowing for cis-trans isomerism.