See image — Isomerism and Stereochemistry Chemistry Question

💡 Solution & Explanation

# Analysis of Isomerism Type **Step 1: Identify the molecular formula of both compounds** Left compound: $C_6H_4Cl-CO-O-C_6H_4-CH=CH-CH_3$ Right compound: $C_6H_5-CO-O-C_6H_4Cl-CH(CH_3)_2$ Both have the same molecular formula: $C_{16}H_{15}ClO_2$ **Step 2: Examine the functional groups** - **Left structure**: Contains a ketone carbonyl ($-CO-$), an ester linkage ($-COO-$), and an alkene ($C=C$) - **Right structure**: Contains only a ketone carbonyl ($-CO-$) and an ester linkage ($-COO-$), with an alkane chain instead of an alkene **Step 3: Define metamerism** Metamerism occurs when isomers have the same molecular formula and functional groups, but differ in the arrangement of carbon atoms around the heteroatom (in this case, oxygen in the ester group). **Step 4: Apply the definition** The two structures differ in: - How the carbon skeleton is distributed on either side of the ester oxygen - Both retain the same functional groups (ketone and ester) - The alkene vs. alkane difference represents rearrangement of the carbon chain **Answer: (C) Metamerism** — The isomers have identical functional groups but different carbon chain arrangements around the ester oxygen atom.