See image — Isomerism and Stereochemistry Chemistry Question

💡 Solution & Explanation

# Solution: Identifying Asymmetric Carbon Atoms An **asymmetric carbon** (chiral center) has four different groups attached to it. **Analyzing each option:** **(A)** $H-C(Cl)(H)-C(Br)(H)-H$ - Left C: H, H, Cl, C → **Two H atoms** (identical) → Not asymmetric - Right C: Br, H, H, C → **Two H atoms** (identical) → Not asymmetric **(B)** $H-C(H)-C(Cl)(H)-Cl$ - Left C: H, H, H, C → **Three H atoms** (identical) → Not asymmetric - Right C: Cl, H, Cl, C → **Two Cl atoms** (identical) → Not asymmetric **(C)** $H-C(H)(H)-C(Cl)(H)-H$ - Left C: H, H, H, C → **Three H atoms** (identical) → Not asymmetric - Right C: Cl, H, H, C → **Two H atoms** (identical) → Not asymmetric **(D)** $H-C(H)(Br)-C(OH)(H)-CH_3$ - Left C: **H, Br, H, C** → Two H atoms → Not asymmetric - Right C: **OH, H, $CH_3$, C(first carbon)** → All four groups are **different** ✓ → **Asymmetric!** **Answer: (D)** is correct because the right carbon atom bears four distinct groups: $-OH$, $-H$, $-CH_3$, and the $-CHBr-$ chain.