See image — Isomerism and Stereochemistry Chemistry Question

💡 Solution & Explanation

# Solution **Analyzing the stereochemistry of M, N, O, P, and Q:** **Step 1: Identify the stereogenic center in M** M has one chiral carbon (marked with *) bearing: HO, H, Cl, Cl, and CH₃. Wait—Cl appears twice, so M is NOT chiral. Actually, examining more carefully: the carbon has HO, Cl, Cl, and CH₃ groups (two Cls make it achiral). Let me reconsider: M has a stereogenic center with: HO, H, Cl, and CH₃ on one carbon, and Cl and CH₃ on another. M is a chiral molecule. **Step 2: Compare M and N** - **M**: HO and Cl on top carbon; Cl and CH₃ on bottom carbon - **N**: HO and CH₃ on top carbon; Cl and OH on bottom carbon Assigning R/S configurations to both carbons: - **M**: Both chiral centers have specific (R,S) or (S,R) configuration - **N**: The substituents are rearranged—these are **diastereomers** (non-mirror images, not enantiomers) **Step 3: Compare M and P** - **P**: Fischer projection shows HO, H at top; Cl, CH₃ at sides; OH, H at bottom - **M**: Comparing the 3D orientation and substituent positions Converting M's wedge-dash to Fischer or vice versa: **P and M have opposite configurations at both stereogenic centers**, making them **enantiomers** (mirror images). ✓ Statement (C) is correct. **Step 4: Compare M and Q** - **Q**: HO, H at top; Cl, CH₃ at sides; OH, H at bottom (same as P arrangement) - **P and Q**: Both show identical connectivity and stereochemistry in the Newman projections Since P and Q are identical structures, **M and Q must also have identical stereochemistry** (as M = Q). Statement **(D) M and Q are identical** is correct. **Answer: (D)**