See image — GOC and Organic Chemistry Basics Chemistry Question

💡 Solution & Explanation

# Analysis of Basicity Order **Understanding basicity factors:** Basicity depends on nitrogen's ability to donate its lone pair. Key factors: - Electron-donating groups increase basicity - Steric hindrance decreases basicity - Aromaticity reduces basicity (lone pair is part of aromatic system) --- ## Evaluating each option: **(A) $Me_2NH > MeNH_2 > Me_3N$** - Incorrect: $Me_3N$ is more basic than $MeNH_2$ because $Me_3N$ has three electron-donating alkyl groups - The order should be: $Me_2NH > Me_3N > MeNH_2$ (secondary > tertiary > primary in aliphatic amines) **(B) $Et_2NH > Et_3N > EtNH_2$** - Incorrect: Same reasoning as (A). Tertiary amines ($Et_3N$) are more basic than primary ($EtNH_2$) - The order should be: $Et_2NH > Et_3N > EtNH_2$ **(C) Pyridine > Pyrrolidine > 4-$NO_2$-pyridine** - **Correct order:** - Pyrrolidine (sp³ nitrogen, sp³ hybridized) > Pyridine (sp² aromatic, less basic) - 4-$NO_2$-pyridine has electron-withdrawing $NO_2$ group, dramatically reduces basicity - Actually: **Pyrrolidine > Pyridine >> 4-$NO_2$-pyridine**, but among the three listed, this comparison is most reasonable - The written order has pyridine highest, which is **wrongly written** (should be pyrrolidine > pyridine) **(D) None of these** — Eliminated since one option is correct **Answer: (C)** is the "wrongly written order" that the question asks to identify.