See image — GOC and Organic Chemistry Basics Chemistry Question

💡 Solution & Explanation

# Analysis: Compounds Reacting with $NaHCO_3$ to Give Sodium Salt and $CO_2$ **Key Requirement:** The compound must be acidic enough to protonate $HCO_3^-$, releasing $CO_2$. $$\text{Compound-H} + NaHCO_3 \rightarrow \text{Compound-Na} + H_2O + CO_2$$ --- ## Evaluation of Each Option: **(A) Phenol** — Weakly acidic ($pK_a \approx 10$) - Does NOT react with $NaHCO_3$ because phenol is too weak to protonate $HCO_3^-$ - Requires stronger base like $NaOH$ **(B) Acetic Acid** — Carboxylic acid ($pK_a \approx 4.75$) ✓ $$CH_3COOH + NaHCO_3 \rightarrow CH_3COONa + H_2O + CO_2$$ - Sufficiently acidic to release $CO_2$ from bicarbonate **(C) Cyclohexanesulfonic Acid** — Strong acid ($pK_a \approx -3$) ✓ $$\text{C}_6H_{11}SO_3H + NaHCO_3 \rightarrow \text{C}_6H_{11}SO_3Na + H_2O + CO_2$$ - Much stronger than acetic acid, easily protonates $HCO_3^-$ **(D) n-Hexanol** — Alcohol (non-acidic) - Does NOT react; alcohols are extremely weak acids and don't release $CO_2$ --- **Answer: B and C** — Both carboxylic acids and sulfonic acids are sufficiently acidic to react with $NaHCO_3$.