See image — GOC and Organic Chemistry Basics Chemistry Question

💡 Solution & Explanation

## Solution: Aromatic Inorganic Compounds **Aromaticity Criteria:** For a compound to be aromatic, it must satisfy Hückel's rule: $(4n+2)$ π electrons in a cyclic, planar, conjugated system. **Analysis of each compound:** **(A) Diborane ($B_2H_6$):** - 3-center-2-electron B-H-B bridges - No aromatic π-electron system - Not aromatic ✗ **(B) Borazole ($B_3N_3H_6$):** - Six-membered ring with alternating B and N atoms - Each B contributes one p-orbital, each N contributes one p-orbital with lone pair - Total: **6 π electrons** = $4(1)+2$ (satisfies Hückel's rule) - Planar, cyclic, conjugated system - **Aromatic** ✓ **(C) Silicone:** - Polymer with Si-O backbone - No cyclic conjugated π-system - Not aromatic ✗ **(D) Corundum Crystal ($Al_2O_3$):** - Ionic solid with extended lattice structure - No aromatic character - Not aromatic ✗ **Answer: (B) Borazole** — It's the inorganic analog of benzene with isoelectronic character (6 π electrons) and exhibits aromaticity.