See image — GOC and Organic Chemistry Basics Chemistry Question

💡 Solution & Explanation

# Stability Analysis of Carbon Species **Identify each species:** - **(I)** Formic acid: $H-C(=O)-OH$ (neutral, stable molecule) - **(II)** Enol cation: $H-C^+(=OH)$ (positive charge on carbon with double bond) - **(III)** Carbanion: $H-C^-(-OH)$ (negative charge on carbon) - **(IV)** Carbocation: $H-C^+(–OH)$ (positive charge on carbon, sp² hybridized) **Stability ranking:** 1. **Species (III) - least stable:** Carbanion with negative charge localized on carbon. Very unstable; carbon is not electronegative enough to bear negative charge. 2. **Species (IV) - low stability:** Primary carbocation ($sp^2$ carbon). Carbocations are high-energy intermediates, though stabilized somewhat by C-H hyperconjugation. 3. **Species (II) - moderate stability:** Enol cation. The positive charge is distributed between C and O (resonance); oxygen's electronegativity helps stabilize the charge better than in (IV). 4. **Species (I) - most stable:** Neutral formic acid molecule with no charges. Neutral, fully bonded species are always more stable than charged species. **Increasing order of stability:** $$\text{(III)} < \text{(IV)} < \text{(II)} < \text{(I)}$$ **Answer: (B)** ✓