See image — GOC and Organic Chemistry Basics Chemistry Question

💡 Solution & Explanation

# Solution: Basic Strength Order **Step 1: Analyze option (a) — $\overline{CH_3} > \overline{NH_2} > \overline{OH} > \overline{F}$** Compare conjugate bases (carbanion, amide, hydroxide, fluoride): - $\overline{CH_3}$ (carbanion): Weakest conjugate base → strongest base ✓ - $\overline{NH_2}$ (amide): Strong conjugate base → strong base ✓ - $\overline{OH}$ (hydroxide): Weaker conjugate base → weaker base ✓ - $\overline{F}$ (fluoride): Strongest conjugate base → weakest base ✓ **This order is CORRECT** (stronger bases have weaker conjugate acids; $CH_4$ is weakest acid, $HF$ is strongest) **Step 2: Analyze option (b) — Aniline derivatives** Three bases with increasing electron-donating effects: - **Left (o-methylaniline)**: $CH_3$ at ortho position — steric hindrance reduces resonance donation; **weakest** - **Middle (m-methylaniline)**: $CH_3$ at meta position — no steric hindrance, weak inductive effect; **intermediate** - **Right (2,4-dimethylaniline)**: Two $CH_3$ groups — strong inductive electron donation to $NH_2$; **strongest** Order $\propto$ electron availability at $N$: **CORRECT** ✓ **Step 3: Conclusion** Both option (a) and option (b) correctly show proper basic strength ordering. **Answer: (c) Both are correct**