See image — GOC and Organic Chemistry Basics Chemistry Question

💡 Solution & Explanation

# Analysis of Compounds I and II **Structure Identification:** - Compound (I): Cyclopentadienyl-benzene conjugated system (5-membered + 6-membered rings fused) - Compound (II): Two cyclopentadiene rings joined by a double bond (symmetric structure) --- **Evaluating Each Statement:** **(a) II has greater dipole moment than I** — **FALSE** - Compound I has an asymmetric conjugated system with different ring sizes, creating polarity - Compound II is perfectly symmetric about the central double bond, resulting in dipole moment = 0 - Therefore, I has the greater dipole moment **(b) Covalent character of II is less than I** — **FALSE** - Both compounds have C=C double bonds with similar covalent character - No significant difference exists in covalency between them **(c) I is more soluble in polar solvent than II** — **TRUE** - Compound I possesses a non-zero dipole moment due to its asymmetric structure - Higher polarity in I makes it more compatible with polar solvents (like water, DMSO) - Compound II is nonpolar and symmetric, showing poor solubility in polar solvents - "Like dissolves like" — polar I dissolves better in polar media **(d) None of these** — FALSE (since option C is correct) --- **Answer: (c)** — Compound I's asymmetric conjugated system generates polarity, making it significantly more soluble in polar solvents compared to the symmetric, nonpolar Compound II.