See image β GOC and Organic Chemistry Basics Chemistry Question
Question
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π‘ Solution & Explanation
# Analysis: Which Reaction Gives an Aromatic Product? To identify which reaction yields an aromatic product, we need to consider ring stability and aromaticity requirements (4n+2 Ο electrons in a planar ring). **Option (a): Cyclopentadienone + $H^+$** - Starting material is a 5-membered ring with one C=O - Addition of $H^+$ would protonate the carbonyl, leading to rearrangement or ring-opening - Does not form a stable aromatic system β **Option (b): Cyclopentanedione + $H^+$** β $$\text{Cyclopentanedione} \xrightarrow{H^+} \text{Cyclopentadienyl cation (5-membered ring, 4Ο electrons)}$$ - Protonation and loss of water from one carbonyl generates a **cyclopentadienyl cation** - This is a **5-membered aromatic cation** with 4Ο electrons (4n+2, where n=1) - Forms a stable, aromatic tropylium-like structure - Highly stabilized β **Option (c): Cyclopropylanone + $H^+$** - 3-membered ring ring strain prevents aromaticity - Does not form aromatic product β **Option (d): Cyclobutanedione + $H^+$** - 4-membered ring; would give 4Ο electrons (antiaromatic, 4n where n=1) - Unstable configuration β **Answer: (b)** β The cyclopentanedione forms the cyclopentadienyl cation, a stable 5-membered aromatic cation with 4Ο electrons satisfying HΓΌckel's rule.