Calculate the standard Gibbs free energy change () for the displacement reaction: . The standard free energies of formation () for and are -50.75 and -65.27 kJ/mol respectively.

Question

Calculate the standard Gibbs free energy change ($\Delta G^\circ$) for the displacement reaction: $CH_4(g) + 2Cl_2(g) \rightarrow CCl_4(l) + 2H_2(g)$. The standard free energies of formation ($\Delta_f G^\circ$) for $CH_4(g)$ and $CCl_4(l)$ are -50.75 and -65.27 kJ/mol respectively.

Prashant Kotian · Accepted Answer

Correct answer: A. The free energy of formation for elements in their standard reference states (, ) is strictly zero. By Hess's Law: kJ/mol.

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