Standard entropies of , , and are 60, 40, and 50 J/K-mol. For the reaction , the enthalpy change is -30 kJ. What must the exact temperature be for the reaction to be at thermodynamic equilibrium?

Question

Standard entropies of $X_2$, $Y_2$, and $XY_3$ are 60, 40, and 50 J/K-mol. For the reaction $0.5 X_2 + 1.5 Y_2 \rightleftharpoons XY_3$, the enthalpy change $\Delta H$ is -30 kJ. What must the exact temperature be for the reaction to be at thermodynamic equilibrium?

Prashant Kotian · Accepted Answer

Correct answer: A. The standard entropy change is J/K-mol. At thermodynamic equilibrium, , meaning . Solving for temperature: K.

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