One mole of an ideal monoatomic gas expands isothermally and reversibly from an initial volume of 1 — Thermodynamics and Thermochemistry Chemistry Question

💡 Solution & Explanation

For an isothermal expansion of an ideal gas, the temperature is constant, so $\Delta S_{sys} = nR \ln(V_2/V_1) = 2.303 nR \log(V_2/V_1)$. Substituting the parameters: $\Delta S_{sys} = 2.303 \times 1 \times 2 \times \log(10) = 4.606 \times 1 = 4.606$ cal/K.