The molar internal energy () of a non-ideal gas confined in a rigid vessel follows the relation , wh — Thermodynamics and Thermochemistry Chemistry Question
Question
The molar internal energy ($U$) of a non-ideal gas confined in a rigid vessel follows the relation $U = a + bT + cT^2$, where $a = 20, b = 10, c = 0.02$ in standard SI units. Calculate the entropy change ($\Delta S$) when one mole is heated from 200 K to 400 K. ($\ln 2 = 0.7$)
Answer: A
💡 Solution & Explanation
Constant volume heating means $C_v = dU/dT = b + 2cT$. The entropy change is $\Delta S = \int (C_v/T) dT = \int (b/T + 2c) dT = b \ln(T_2/T_1) + 2c(T_2 - T_1)$. $\Delta S = 10 \ln(2) + 0.04(200) = 10(0.7) + 8 = 15$ J/K.
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