10 g of argon gas is compressed isothermally and reversibly at a temperature of 27 C from 10 L to 5 — Thermodynamics and Thermochemistry Chemistry Question

💡 Solution & Explanation

For an ideal gas isothermal process, $\Delta H = 0$. By the First Law, $q = -w$. Reversible work $w = -2.303 nRT \log(V_2/V_1) = -2.303 \times (10/40) \times 2 \times 300 \times \log(5/10) = +103.99$ cal. Thus, heat exchanged is $q = -w = -103.99$ cal.